Public-domain books

First Course in the Theory of Equations

The Graph of an Equation

Excerpts

Equations

Problems

Exercise Page55

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Exercise Page59

  1. Exercise Page59, problem 1, p. 59

    Show that the slope of the tangent to $y = 8x^3 - 22x^2 + 13x - 2$ at $(x, y)$ is $24x^2 - 44x + 13$, and that the bend points are $(0.37, 0.203)$, $(1.46, -5.03)$, approximately. Draw the graph.

    Printed answer:
    • (none printed)

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    • other: not a kind the checker handles
  2. Exercise Page59, problem 10, p. 59

    Prove that if $g$ and $k$ are polynomials in $x$, the derivative of $gk$ is $g'k + gk'$. Hint: multiply the members of $g(x+h) = g(x) + g'(x)h + \dotsb$ and $k(x+h) = k(x) + k'(x)h + \dotsb$ and use $(8)$ for $f = gk$.

    Printed answer:
    • (none printed)

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    • other: not a kind the checker handles
  3. Exercise Page59, problem 2, p. 59

    Prove that the bend points of $y = x^3 - 2x - 5$ are $(.82, -6.09)$, $(-.82$, $-3.91)$, % [** PP: Allow line break between coordinates] approximately. Draw the graph and locate the real roots.

    Printed answer:
    • $2.1$.

    verified: the printed answer passed a computed check

    How it was checked
    • solve: passes 2.1
  4. Exercise Page59, problem 3a, p. 59

    Find the bend points of $y = x^3 + 6x^2 + 8x + 8$. Locate the real roots.

    Printed answer:
    • $(-0.845, 4.921)$, $(-3.155, 11.079)$

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    • other: not a kind the checker handles
  5. Exercise Page59, problem 3b, p. 59

    Find the bend points of $y = x^3 + 6x^2 + 8x + 8$. Locate the real roots.

    Printed answer:
    • between $-4$ and $-5$.

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    • other: not a kind the checker handles
  6. Exercise Page59, problem 4, p. 59

    Locate the real roots of $f(x) = x^4 + x^3 - x - 2 = 0$. Hints: The abscissas of the bend points are the roots of $f'(x) = 4x^3 + 3x^2 - 1 = 0$. The bend points of $y = f'(x)$ are $(0, -1)$ and $(-\frac{1}{2}, -\frac{3}{4})$, so that $f'(x)= 0$ has a single real root (it is just less than $\frac{1}{2}$). The single bend point of $y=f(x)$ is $(\frac{1}{2}, -\frac{37}{16})$, approximately.

    Printed answer:
    • $1.1$, $-1.3$.

    verified: the printed answer passed a computed check

    How it was checked
    • solve: passes [1.1, -1.3]
  7. Exercise Page59, problem 5, p. 59

    Locate the real roots of $x^6 - 7x^4 - 3x^2 + 7 = 0$.

    Printed answer:
    • Between $0$ and $1$, $0$ and $-1$, $2.5$ and $3$, $-2.5$ and $-3$.

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  8. Exercise Page59, problem 6, p. 59

    Prove that $f''(x)$, given by $(7)$, is equal to the first derivative of $f'(x)$.

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    • (none printed)

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  9. Exercise Page59, problem 7, p. 59

    If $f(x) = f_1(x) + f_2(x)$, prove that the $k$th derivative of $f$ is equal to the sum of the $k$th derivatives of $f_1$ and $f_2$. Use $(8)$.

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    • (none printed)

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  10. Exercise Page59, problem 8, p. 59

    Prove that $f^{(k)}(x)$ is equal to the first derivative of $f^{(k-1)}(x)$. Hint: prove this for $f = ax^m$; then prove that it is true for $f=f_1 + f_2$ if true for $f_1$ and $f_2$.

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    • (none printed)

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  11. Exercise Page59, problem 9a, p. 59

    Find the third derivative of $x^6 + 5x^4$ by forming successive first derivatives; also that of $2x^5 - 7x^3 + x$.

    Printed answer:
    • $120(x^3 + x)$

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    • differentiate: the printed answer does not match the problem 120*(x**3 + x)
  12. Exercise Page59, problem 9b, p. 59

    Find the third derivative of $x^6 + 5x^4$ by forming successive first derivatives; also that of $2x^5 - 7x^3 + x$.

    Printed answer:
    • $120x^2 - 42$.

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    How it was checked
    • differentiate: the printed answer does not match the problem 120*x**2 - 42

Exercise Page62

  1. Exercise Page62, problem 1, p. 62

    Prove that $x^3 - 7x^2 + 15x - 9 = 0$ has a double root.

    Printed answer:
    • $3$.

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    • other: not a kind the checker handles 3
  2. Exercise Page62, problem 2, p. 62

    Show that $x^4 - 8x^2 + 16 = 0$ has two double roots.

    Printed answer:
    • $2$, $-2$.

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    • other: not a kind the checker handles [2, -2]
  3. Exercise Page62, problem 3, p. 62

    Prove that $x^4 - 6x^2 - 8x - 3 = 0$ has a triple root.

    Printed answer:
    • $-1$.

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    • other: not a kind the checker handles -1
  4. Exercise Page62, problem 4, p. 62

    Test $x^4 - 8x^3 + 22x^2 - 24x + 9 = 0$ for multiple roots.

    Printed answer:
    • Double roots, $1$, $3$.

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    • other: not a kind the checker handles [1, 3]
  5. Exercise Page62, problem 5, p. 62

    Test $x^3 - 6x^2 + 11x - 6 = 0$ for multiple roots.

    Printed answer:
    • None.

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    • other: not a kind the checker handles []
  6. Exercise Page62, problem 6, p. 62

    Test $x^4 - 9x^3 + 9x^2 + 81x - 162 = 0$ for multiple roots.

    Printed answer:
    • $3$, $3$, $-3$, $6$.

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    How it was checked
    • other: not a kind the checker handles [3, 3, -3, 6]

Exercise Page64

  1. Exercise Page64, problem 1, p. 64

    If $f(x) = 3x^5 + 5x^3 + 4$, the only real root of $f'(x)=0$ is $x = 0$. Show that $(0, 4)$ inflexion point, and thus that there is no bend point and hence that $f(x)=0$ has a single real root.

    Printed answer:
    • (none printed)

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    • other: the record may be misread
  2. Exercise Page64, problem 2, p. 64

    Prove that $x^3 - 3x^2 + 3x + c = 0$ has an inflexion point, but no bend point.

    Printed answer:
    • (none printed)

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    • other: not a kind the checker handles
  3. Exercise Page64, problem 3, p. 64

    Show that $x^5 - 10x^3 - 20x^2 - 15x + c = 0$ has two bend points and no horizontal inflexion tangents.

    Printed answer:
    • Use Ex. 3, p. 62, abscissas $-1$, $3$.

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  4. Exercise Page64, problem 4, p. 64

    Prove that $3x^5 - 40x^3 + 240x + c = 0$ has no bend point, but has two horizontal inflexion tangents.

    Printed answer:
    • Use Ex. 2, p. 62.

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  5. Exercise Page64, problem 5, p. 64

    Prove that any function $x^3 - 3\alpha x^2 + \dotsb$ of the third degree can be written in % [** PP: Not using page range] the form $f(x) = (x-\alpha)^3 + ax + b$. The straight line having the equation $y = ax+b$ meets the graph of $y=f(x)$ in three coincident points with the abscissa $\alpha$ and hence is an inflexion tangent. If we take new axes of coordinates parallel to the old and intersecting at the new origin $(\alpha, 0)$, i.e., if we make the transformation $x = X+\alpha$, $y = Y$, %% -----File: 071.png---Folio 65------- of coordinates, we see that the equation $f(x)=0$ becomes a reduced cubic equation $X^3 + pX + q = 0$ (§42).

    Printed answer:
    • (none printed)

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  6. Exercise Page64, problem 6, p. 64

    Find the inflexion tangent to $y = x^3 + 6x^2 - 3x + 1$ and transform $x^3 + 6x^2 - 3x + 1 = 0$ into a reduced cubic equation.

    Printed answer:
    • $y = -15x - 7$, $X^3 - 15X + 23 = 0$.

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Exercise Page66

  1. Exercise Page66, problem 1, p. 66

    $x^3 + 2x - 4 = 0$.

    Printed answer:
    • One real.

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    • other: not a kind the checker handles
  2. Exercise Page66, problem 10, p. 66

    Prove that no straight line crosses the graph of $y = f(x)$ in more than $n$ points if the degree $n$ of the real polynomial $f(x)$ exceeds unity. [Apply §16.] This fact serves as a check on the accuracy of a graph.

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    • (none printed)

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  3. Exercise Page66, problem 2, p. 66

    $x^3 - 7x + 7 = 0$.

    Printed answer:
    • $(±\sqrt{\frac{7}{3}}, 7\mp\frac{14}{3}\sqrt{\frac{7}{3}})$, three real.

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    • other: not a kind the checker handles
  4. Exercise Page66, problem 3, p. 66

    $x^3 - 2x - 1 = 0$.

    Printed answer:
    • $(±\sqrt\frac{2}{3}, -1\mp\frac{4}{3}\sqrt{\frac{2}{3}})$, three.

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    • other: not a kind the checker handles
  5. Exercise Page66, problem 4, p. 66

    $x^3 + 6x^2 - 3x + 1 = 0$.

    Printed answer:
    • $(-2±\sqrt{5}, 23\mp10\sqrt{5})$, one.

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    • other: not a kind the checker handles
  6. Exercise Page66, problem 5, p. 66

    Prove that the inflexion point of $y = x^3 - 3lx + q$ is $(0, q)$.

    Printed answer:
    • (none printed)

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  7. Exercise Page66, problem 6, p. 66

    Show that the theorem in the text is equivalent to that in §45.

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    • (none printed)

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  8. Exercise Page66, problem 7, p. 66

    Prove that, if $m$ and $n$ are positive odd integers and $m>n$, $x^m + px^n + q = 0$ has no bend point and hence has a single real root if $p>0$; but, if $p<0$, it has just two bend points which are on the same side or opposite sides of the $x$-axis according as (npm)^m + (nqm-n)^m-n is positive or negative, so that the number of real roots is $1$ or $3$ in the respective cases.

    Printed answer:
    • (none printed)

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    • other: not a kind the checker handles
  9. Exercise Page66, problem 8, p. 66

    Draw the graph of $y = x^4 - x^2$. By finding its intersections with the line $y = mx + b$, solve $x^4 - x^2 - mx - b= 0$.

    Printed answer:
    • (none printed)

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    • solve: no printed answer to check
  10. Exercise Page66, problem 9, p. 66

    Prove that, if $p$ and $q$ are positive, $x^{2m} - px^{2n} + q = 0$ has four distinct real roots, two pairs of equal roots, or no real root, according as (npm)^m - (nqm-n)^m-n > 0, ${} = 0$, or ${} < 0$.

    Printed answer:
    • (none printed)

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Exercise Page68

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Exercise Page69

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Exercise Page70

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