Vector Analysis and Quaternions
Composition of Quantities
Excerpts
Composition of Quantities
The equation states that the mass $m$ at the extremity of the vector $A$ is equivalent to the equal mass at the extremity of $R$, together with the said mass-vector applied at the extremity of $R$.
Composition of Quantities
This equation asserts that a force $F$ applied at the extremity of $A$ is equivalent to an equal force applied at the extremity of $R$ together with a couple whose magnitude and direction are given by the vector product of the radius-vector from the extremity of $R$ to the extremity of $A$ and the force.
Composition of Quantities
The product $m(A - R)$ is what Clerk Maxwell called a mass-vector, and means the directed moment of $m$ with respect to the extremity of $R$.
Composition of Quantities
The term (2) means the projection of $R$ upon that line.
Composition of Quantities
This is the same straight line as before, only no relation is now imposed on the directions of $\sum F$ and $\sum \mathrm{V}AF$; hence there always is a central axis.
Equations
Composition of Quantities
\sum m_A = \sum m_R + \sum\Bigl\{m(A - R)\Bigr\}For any number of masses, the total mass at A equals the total mass at R plus the sum of the mass-vectors about R.
Composition of Quantities
R = \frac{\sum mA}{\sum m},\quad\text{or}\quad R \sum m = \sum mAThe resultant moment of the masses vanishes when R is the point at the weighted mean position of the masses, which is the centre of mass.
Composition of Quantities
x &= \frac{\sum (ma)}{\sum m}The x-coordinate of the centre of mass is the mass-weighted mean of the x-coordinates of the masses.
Composition of Quantities
y = \frac{\sum (mb)}{\sum m}The y-coordinate of the centre of mass is the mass-weighted mean of the y-coordinates of the masses.
Composition of Quantities
z = \frac{\sum (mc)}{\sum m}The z-coordinate of the centre of mass is the mass-weighted mean of the z-coordinates of the masses.
Composition of Quantities
A &= a_1j + b_1j+c_1k;The radius-vector A is written in components a, b, c along the coordinate axes.
Composition of Quantities
F_A &= F_R + \mathrm{V}(A-R)FA force F applied at A is equivalent to an equal force at R together with a couple given by the vector product of the vector from R to A and the force.
Composition of Quantities
\sum \left(F_A\right) &= \sum \left(F_R\right) + \sum \mathrm{V}\left(A - R\right)FFor a system of forces at different points, the forces at A equal the forces at R plus the sum of the couples about R.
Composition of Quantities
\mathrm{V} R \sum F &= \sum \mathrm{V} A FThere is no resultant couple when the vector product of R with the resultant force equals the sum of the vector products of each point with its force.
Composition of Quantities
R &= \frac{1}{\sum F}\sum \left(\mathrm{V}AF \right) \tag{1}The vector term (1) is perpendicular to the resultant force and fixes the line along which R must lie for the resultant couple to vanish.
Composition of Quantities
\mathrm{V}\left\{\sum \mathrm{V}AF - \mathrm{V}R\sum F\right\} \sum F = 0On the central axis the resultant force and the resultant couple have the same direction.
Problems
Exercise Probs-44-47
Exercise Probs-44-47, problem 44
Find the moment at $\overline{90^\circ/}\! \underline{/270^\circ}$ of 10 pounds at 4 feet $\overline{10^\circ/}\!\underline{/20^\circ}$ and 20 pounds at 5 feet $\overline{30^\circ/}\!\underline{/120^\circ}$.
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Exercise Probs-44-47, problem 45
Find the torque for $4i + 3j + 2k$ pounds weight at $2i - 3j + 1k$ feet, and $2i - 1k - 1k$ pounds weight at $-3i + 4j + 5k$ feet when transferred to $-3i -2j -4k$ feet.
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Exercise Probs-44-47, problem 46
Find the central axis in the above case.
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Exercise Probs-44-47, problem 47
Prove that the mass-vector drawn from any origin to a mass equal to that of the whole system placed at the center of mass of the system is equal to the sum of the mass-vectors drawn from the same origin to all the particles of the system.
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