Successive Differentiation
Excerpts
Successive Differentiation
Begin with a concrete case.
Successive Differentiation
This is called the “derived function” of $x$.
Successive Differentiation
So the statement $y=f(x)$ merely tells us that $y$ is a function of $x$, it may be $x^2$ or $ax^n$, or $\cos x$ or any other complicated function of $x$.
Successive Differentiation
This is to employ the general symbol $f(x)$ for any function of $x$. Here the symbol $f(~)$ is read as “function of,” without saying what particular function is meant. So the statement $y=f(x)$ merely tells us that $y$ is a function of $x$, it may be $x^2$ or $ax^n$, or $\cos x$ or any other complicated function of $x$.
Successive Differentiation
The corresponding symbol for the differential coefficient is $f'(x)$, which is simpler to write than $\dfrac{dy}{dx}$. This is called the “derived function” of $x$.
Successive Differentiation
Suppose we differentiate over again, we shall get the “second derived function” or second differential coefficient, which is denoted by $f''(x)$; and so on.
Successive Differentiation
Similarly, we may write as the result of thrice differentiating, $\dfrac{d^3y}{dx^3} = f'''(x)$.
Equations
Successive Differentiation
y = x^5The concrete function y = x^5 is differentiated repeatedly as a first example of successive differentiation.
Successive Differentiation
y = f(x) = x^nA general power function y = f(x) = x^n is introduced to generalise the repeated differentiation.
Successive Differentiation
f'(x) &= nx^{n-1}The first derivative of x^n is n x^(n-1).
Successive Differentiation
f''(x) &= n(n-1)x^{n-2}The second derivative of x^n is n(n-1) x^(n-2).
Successive Differentiation
f'''(x) &= n(n-1)(n-2)x^{n-3}The third derivative of x^n is n(n-1)(n-2) x^(n-3).
Successive Differentiation
f''''(x) &= n(n-1)(n-2)(n-3)x^{n-4}The fourth derivative of x^n is n(n-1)(n-2)(n-3) x^(n-4).
Successive Differentiation
y &= f(x)The original function is written y = f(x), so y is a function of x.
Successive Differentiation
\frac{dy}{dx} = f'(x)The differential coefficient of y with respect to x is denoted f'(x), the derived function.
Successive Differentiation
\frac{d\left(\dfrac{dy}{dx}\right)}{dx} &= f''(x)Differentiating dy/dx again gives the second derived function f''(x).
Successive Differentiation
\dfrac{d^3y}{dx^3} = f'''(x)Thrice differentiating y with respect to x is written d^3y/dx^3 and equals f'''(x).
Successive Differentiation
y = f(x) = 7x^4 + 3.5x^3 - \frac{1}{2}x^2 + x - 2A specific polynomial y = f(x) is chosen as an example for successive differentiation.
Successive Differentiation
\frac{dy}{dx} &= f'(x) = 28x^3 + 10.5x^2 - x + 1The first derivative of the example polynomial is 28x^3 + 10.5x^2 - x + 1.
Successive Differentiation
\frac{d^2y}{dx^2} &= f''(x) = 84x^2 + 21x - 1The second derivative of the example polynomial is 84x^2 + 21x - 1.
Successive Differentiation
\frac{d^3y}{dx^3} &= f'''(x) = 168x + 21The third derivative of the example polynomial is 168x + 21.
Successive Differentiation
\frac{d^4y}{dx^4} &= f''''(x) = 168The fourth derivative of the example polynomial is the constant 168.
Successive Differentiation
\frac{d^5y}{dx^5} &= f'''''(x) = 0The fifth derivative of the example polynomial is zero.
Successive Differentiation
y = \phi(x) = 3x(x^2 - 4)A second example function y = phi(x) = 3x(x^2 - 4) is given for successive differentiation.
Successive Differentiation
\phi'(x) &= \frac{dy}{dx} = 3\bigl[x × 2x + (x^2 - 4) × 1\bigr] = 3(3x^2 - 4)The first derivative of 3x(x^2 - 4) is 3(3x^2 - 4), obtained by the product rule.
Successive Differentiation
\phi''(x) &= \frac{d^2y}{dx^2} = 3 × 6x = 18xThe second derivative of the second example function is 18x.
Successive Differentiation
\phi'''(x) &= \frac{d^3y}{dx^3} = 18The third derivative of the second example function is the constant 18.
Successive Differentiation
\phi''''(x) &= \frac{d^4y}{dx^4} = 0The fourth derivative of the second example function is zero.
Problems
Exercise IV
Exercise IV, problem 1a, p. 51
$y = 17x + 12x^2$.
Printed answer:- $17 + 24x$; $24$.
verified: the printed answer passed a computed check
How it was checked
differentiate: passes17 + 24*x
Exercise IV, problem 1b, p. 51
$y = 17x + 12x^2$.
Printed answer:- $17 + 24x$; $24$.
verified: the printed answer passed a computed check
How it was checked
differentiate2: passes24
Exercise IV, problem 2a, p. 51
$y = \dfrac{x^2 + a}{x + a}$.
Printed answer:- $\dfrac{x^2 + 2ax - a}{(x + a)^2}$; $\dfrac{2a(a + 1)}{(x + a)^3}$.
verified: the printed answer passed a computed check
How it was checked
differentiate: passes(x**2 + 2*a*x - a)/(x + a)**2
Exercise IV, problem 2b, p. 51
$y = \dfrac{x^2 + a}{x + a}$.
Printed answer:- $\dfrac{x^2 + 2ax - a}{(x + a)^2}$; $\dfrac{2a(a + 1)}{(x + a)^3}$.
verified: the printed answer passed a computed check
How it was checked
differentiate2: passes2*a*(a + 1)/(x + a)**3
Exercise IV, problem 3a, p. 51
$y = 1 + \dfrac{x}{1} + \dfrac{x^2}{1×2} + \dfrac{x^3}{1×2×3} + \dfrac{x^4}{1×2×3×4}$.
Printed answer:- $1 + x + \dfrac{x^2}{1 × 2} + \dfrac{x^3}{1 × 2 × 3}$
verified: the printed answer passed a computed check
How it was checked
differentiate: passes1 + x + x**2/(1*2) + x**3/(1*2*3)
Exercise IV, problem 3b, p. 51
$y = 1 + \dfrac{x}{1} + \dfrac{x^2}{1×2} + \dfrac{x^3}{1×2×3} + \dfrac{x^4}{1×2×3×4}$.
Printed answer:- $1 + x + \dfrac{x^2}{1 × 2}$.
verified: the printed answer passed a computed check
How it was checked
differentiate2: passes1 + x + x**2/(1*2)
Exercise IV, problem 4, p. 51
Find the 2nd and 3rd derived functions in the Exercises III. (examples2), No. 1 to No. 7, and in the Examples given (examples3), No. 1 to No. 7.
Printed answer:- (*Exercises III.*): itemize [(1)] (*a*) $\dfrac{d^2 y}{dx^2} = \dfrac{d^3 y}{dx^3} = 1 + x + \frac{1}{2}x^2 + \frac{1}{6} x^3 + \ldots$. (*b*) $2a$, $0$. (*c*) $2$, $0$. (*d*) $6x + 6a$, $6$. 268.png256% [(2)] $-b$, $0$.(3) $2$, $0$. [(4)] $\begin{gathered}[t] 56440x^3 - 196212x^2 - 4488x + 8192. \\ 169320x^2 - 392424x - 4488. \end{gathered}$ [(5)] $2$, $0$. (6) $371.80453x$, $371.80453$. [(7)] $\dfrac{30}{(3x + 2)^3}$, $-\dfrac{270}{(3x + 2)^4}$. itemize (*Examples*, examples3): itemize [(1)] $\dfrac{6a}{b^2} x$, $\dfrac{6a}{b^2}$.(2) $\dfrac{3a \sqrt{b}} {2 \sqrt{x}} - \dfrac{6b \sqrt[3]{a}}{x^3}$, $\dfrac{18b \sqrt[3]{a}}{x^4} - \dfrac{3a \sqrt{b}}{4 \sqrt{x^3}}$ (3) $\dfrac{2}{\sqrt[3]{\theta^8}} - \dfrac{1.056}{\sqrt[5]{\theta^{11}}}$, $\dfrac{2.3232}{\sqrt[5]{\theta^{16}}} - \dfrac{16}{3 \sqrt[3]{\theta^{11}}}$. (4) $\begin{gathered}[t] 810t^4 - 648t^3 + 479.52t^2 - 139.968t + 26.64. \\ 3240t^3 - 1944t^2 + 959.04t - 139.968. \end{gathered}$ (5) $12x + 2$, $12$.(6) $6x^2 - 9x$, $12x - 9$. (7) $\begin{aligned}[t] &\dfrac{3}{4} \left(\dfrac{1}{\sqrt{\theta}} + \dfrac{1}{\sqrt{\theta^5}}\right) +\dfrac{1}{4} \left(\dfrac{15}{\sqrt{\theta^7}} - \dfrac{1}{\sqrt{\theta^3}}\right). \\ &\dfrac{3}{8} \left(\dfrac{1}{\sqrt{\theta^5}} - \dfrac{1}{\sqrt{\theta^3}}\right) -\dfrac{15}{8}\left(\dfrac{7}{\sqrt{\theta^9}} + \dfrac{1}{\sqrt{\theta^7}}\right). \end{aligned}$ itemize
unverified: no computed check settled this one (yet)
How it was checked
other: the record may be misread