Spherical Trigonometry, for the Use of Colleges and Schools
Polyhedrons
Excerpts
Polyhedrons
A polyhedron is a solid bounded by any number of plane rectilineal figures which are called its faces.
Polyhedrons
It will be seen that the demonstration establishes something more than the enunciation states; for it is not assumed that the faces are equilateral and equiangular and all equal.
Polyhedrons
If $\mathrm{S}$ be the number of solid angles in any polyhedron, $\mathrm{F}$ the number of its faces, $\mathrm{E}$ the number of its edges, then $\mathrm{S+F=E+2}$.
Polyhedrons
Take any point within the polyhedron as centre, and describe a sphere of radius $r$, and draw straight lines from the centre to each of the angular points of the polyhedron;
Polyhedrons
but $n$ cannot be less than 3, so that $\dfrac{1}{n}$ cannot be greater than $\dfrac{1}{3}$,
Polyhedrons
Thus for a *regular* tetrahedron we have $144\hspace{3pt}V^2=2a^6$.
Polyhedrons
A regular octahedron is inscribed in a cube so that the corners of the octahedron are at the centres of the faces of the cube: shew that the volume of the cube is six times that of the octahedron.
Polyhedrons
Or we may adopt Carnot’s method, in which this relation is established independently, and the expression for the volume of a tetrahedron is deduced from it;
Equations
Polyhedrons
\mathrm{S+F=E+2}In any polyhedron, the number of solid angles plus the number of faces equals the number of edges plus two.
Polyhedrons
r^2\{s-(m-2)\pi\}The area of a spherical polygon with m sides and angle sum s, on a sphere of radius r, is r squared times s minus (m-2) pi.
Polyhedrons
4\pi r^2The surface area of a sphere of radius r is 4 pi r squared.
Polyhedrons
2(S-2)\piThe sum of all the plane angles forming the solid angles of any polyhedron is 2(S-2) pi.
Polyhedrons
mF=nS=2EFor a regular polyhedron, the total number of plane angles counted by faces (m F), by solid angles (n S), or by edges (2E) is the same.
Polyhedrons
S = \frac{4 m}{2(m+n)-mn}The number of solid angles of a regular polyhedron is 4m divided by 2(m+n) minus mn.
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E = \frac{2mn}{2(m+n)-mn}The number of edges of a regular polyhedron is 2mn divided by 2(m+n) minus mn.
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F = \frac{4 n}{2(m+n)-mn}The number of faces of a regular polyhedron is 4n divided by 2(m+n) minus mn.
Polyhedrons
\frac{1}{m}+\frac{1}{n} \text{ must be greater than } \frac{1}{2}For a regular polyhedron to exist, 1/m + 1/n must be greater than 1/2.
Polyhedrons
\sin{\frac{I}{2}}=\frac{\cos \dfrac{\pi}{n}} {\sin{\dfrac{\pi}{m}}}The sine of half the inclination of two adjacent faces of a regular polyhedron equals cos(pi/n) divided by sin(pi/m).
Polyhedrons
CE = AE\cot{ACE} = \frac{a}{2}\cot{\frac{\pi}{m}}The perpendicular CE from the centre of a face to the midpoint E of an edge equals half the edge times the cotangent of pi/m.
Polyhedrons
r = CE\tan{CEO} = CE\tan{\frac{I}{2}} = \frac{a}{2}\cot{\frac{\pi}{m}}\tan{\frac{I}{2}}The radius r of the sphere inscribed in a regular polyhedron equals (a/2) cot(pi/m) tan(I/2).
Polyhedrons
r = R\cos{aOc} = R\cot{eca}\cot{eac} = R\cot{\frac{\pi}{m}} \cot{\frac{\pi}{n}}The inscribed-sphere radius r equals the circumscribed-sphere radius R times cot(pi/m) times cot(pi/n).
Polyhedrons
R = r\tan{\frac{\pi}{m}} \tan{\frac{\pi}{n}} = \frac{a}{2} \tan{\frac{I}{2}} \tan{\frac{\pi}{n}}The circumscribed-sphere radius R of a regular polyhedron equals r tan(pi/m) tan(pi/n), or (a/2) tan(I/2) tan(pi/n).
Polyhedrons
\dfrac{ma^2}{4}\cot{\dfrac{\pi}{m}}The area of one face of a regular polyhedron with m sides and edge a is (m a^2 /4) cot(pi/m).
Polyhedrons
\dfrac{mFa^2}{4}\cot{\dfrac{\pi}{m}}The surface of a regular polyhedron equals (m F a^2/4) cot(pi/m).
Polyhedrons
\dfrac{mFra^2}{12}\cot{\dfrac{\pi}{m}}The volume of a regular polyhedron equals (m F r a^2 /12) cot(pi/m), with r the radius of the inscribed sphere.
Polyhedrons
= abc\surd{( 1 - \cos^2{\alpha} - \cos^2{\beta} - \cos^2{\gamma} + 2\cos{\alpha} \cos{\beta} \cos{\gamma} )}The volume of a parallelepiped with edges a, b, c from one vertex and inclinations alpha, beta, gamma is abc times the square root of 1 minus the squared cosines plus twice the product of the cosines.
Polyhedrons
OD^2 = a^2+b^2+c^2 + 2ab\cos{\gamma} + 2bc\cos{\alpha} + 2ca\cos{\beta}The squared length of the diagonal OD of a parallelepiped equals the sum of the squares of the three edges plus twice each product of two edges times the cosine of their inclination.
Polyhedrons
144\hspace{3pt}V^2=2a^6For a regular tetrahedron of edge a, 144 V squared equals 2 a to the sixth power.
Polyhedrons
144\hspace{3pt}V^2 = -a'^2 b'^2 c'^2 + a^2a'^2 (b'^2+c'^2-a'^2) + b^2b'^2 (c'^2+a'^2-b'^2) + c^2c'^2 (a'^2+b'^2-c'^2) - a'^2 (a^2-b^2) (a^2-c^2) - b'^2 (b^2-c^2) (b^2-a^2) - c'^2 (c^2-a^2) (c^2-b^2)The volume of a tetrahedron is expressed in terms of its six edges by this relation, with a, b, c the three edges at one vertex and a', b', c' the opposite edges.
Polyhedrons
\cos{ADB}=\dfrac{a'^2+b'^2-c^2}{2a'b'}In triangle ADB, the cosine of the angle at D equals (a'^2 + b'^2 - c^2) divided by 2a'b', where c is the side AB.
Polyhedrons
1=\cos^2{ADB}+\cos^2{BDC}+\cos^2{CDA}-2\cos{ADB}\cos{BDC}\cos{CDA}For four points in a plane with D joined to A, B, C, the squared cosines of the three angles at D, minus twice their product, equal 1.
Polyhedrons
0=-a^2b^2c^2 + a'^2a^2(b^2+c^2-a^2) + b'^2b^2(c^2+a^2-b^2) + c'^2c^2(a^2+b^2-c^2) - a^2(a'^2-b'^2)(a'^2-c'^2) - b^2(b'^2-c'^2)(b'^2-a'^2) - c^2(c'^2-a'^2)(c'^2-b'^2)The six straight lines joining four points taken arbitrarily in a plane satisfy this relation.
Polyhedrons
p^2(2a^2b^2+2b^2c^2+2c^2a^2 -a^4-b^4-c^4) = -a^2b^2c^2 + a'^2a^2(b^2+c^2-a^2) + b'^2b^2(c^2+a^2-b^2) + c'^2c^2(a^2+b^2-c^2) - a^2(a'^2-b'^2)(a'^2-c'^2) - b^2(b'^2-c'^2)(b'^2-a'^2) - c^2(c'^2-a'^2)(c'^2-b'^2)With p the altitude of a tetrahedron on a base triangle of sides a, b, c and lateral edges a', b', c', the left side equals 144 V squared, giving the volume in terms of the six edges.
Polyhedrons
\cos{ADB}=\dfrac{\cos{\gamma}-\cos{\alpha'}\cos{\beta'}} {\sin{\alpha'}\sin{\beta}'}On the sphere, the cosine of the angle ADB equals (cos gamma minus cos alpha' cos beta') divided by sin alpha' sin beta'.
Polyhedrons
\cos{\alpha}=1-2\sin^2{\frac{\alpha}{2}}The cosine of an angle equals one minus twice the squared sine of half that angle.
Polyhedrons
aa'+bb'+cc'=2\sigmaThe quantity sigma is defined as half the sum of the products aa', bb', cc'.
Polyhedrons
36\hspace{3pt}V^2r^2=\sigma(\sigma-aa')(\sigma-bb')(\sigma-cc')The product 36 V squared r squared equals sigma times the three factors sigma minus aa', bb', cc', by analogy with Heron's formula.
Problems
Exercise XIII
Exercise XIII, problem 1, p. 133
If $I$ denote the inclination of two adjacent faces of a regular polyhedron, shew that $\cos I=\tfrac{1}{3}$ in the tetrahedron, $=0$ in the cube, $=-\tfrac{1}{3}$ in the octahedron, $=-\tfrac{1}{5}\surd{5}$ in the dodecahedron, and $=-\tfrac{1}{3}\surd{5}$ in the icosahedron.
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Exercise XIII, problem 10, p. 133
The sum of the squares of the four diagonals of a parallelepiped is equal to four times the sum of the squares of the edges.
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Exercise XIII, problem 11, p. 133
If with all the angular points of any parallelepiped as centres equal spheres be described, the sum of the intercepted portions of the parallelepiped will be equal in volume to one of the spheres.
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Exercise XIII, problem 12, p. 133
A regular octahedron is inscribed in a cube so that the corners of the octahedron are at the centres of the faces of the cube: shew that the volume of the cube is six times that of the octahedron.
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Exercise XIII, problem 13, p. 133
It is not possible to fill any given space with a number of regular polyhedrons of the same kind, except cubes; but this may be done by means of tetrahedrons and octahedrons which have equal faces, by using twice as many of the former as of the latter.
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Exercise XIII, problem 14, p. 133
A spherical triangle is formed on the surface of a sphere of radius $\rho$; its angular points are joined, forming thus a pyramid with the straight lines joining them with the centre: shew that the volume of the pyramid is 13^3(rr_1r_2r_3), where $r$, $r_1$, $r_2$, $r_3$ are the radii of the inscribed and escribed circles of the triangle.
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Exercise XIII, problem 15, p. 133
The angular points of a regular tetrahedron inscribed in a sphere of radius $r$ being taken as poles, four equal small circles of the sphere are described, so that each circle touches the other three. Shew that the area of the surface bounded by each circle is $2\pi r^2\left( 1 - \dfrac{1}{\surd{3}} \right)$.
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Exercise XIII, problem 16, p. 133
If $O$ be any point within a spherical triangle $ABC$, the product of the sines of any two sides and the sine of the included angle multline* =AOBOCO AOBOC +BOCOA+COAOB . multline*
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Exercise XIII, problem 2, p. 133
With the notation of Art. 153, shew that the radius of the sphere which touches one face of a regular polyhedron and all the adjacent faces produced is $\tfrac{1}{2}a\cot{\dfrac{\pi}{m}}\cot{\tfrac{1}{2}}I$.
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Exercise XIII, problem 3, p. 133
A sphere touches one face of a regular tetrahedron and the other three faces produced: find its radius.
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Exercise XIII, problem 4, p. 133
If $a$ and $b$ are the radii of the spheres inscribed in and described about a regular tetrahedron, shew that $b=3a$.
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Exercise XIII, problem 5, p. 133
If $a$ is the radius of a sphere inscribed in a regular tetrahedron, and $R$ the radius of the sphere which touches the edges, shew that $R^2=3a^2$.
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Exercise XIII, problem 6, p. 133
If $a$ is the radius of a sphere inscribed in a regular tetrahedron, and $R'$ the radius of the sphere which touches one face and the others produced, shew that $R'=2a$.
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Exercise XIII, problem 7, p. 133
If a cube and an octahedron be described about a given sphere, the sphere described about these polyhedrons will be the same; and conversely.
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Exercise XIII, problem 8, p. 133
If a dodecahedron and an icosahedron be described about a given sphere, the sphere described about these polyhedrons will be the same; and conversely.
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Exercise XIII, problem 9, p. 133
A regular tetrahedron and a regular octahedron are inscribed in the same sphere: compare the radii of the spheres which can be inscribed in the two solids.
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